Integrand size = 9, antiderivative size = 55 \[ \int \frac {1}{\left (a+\frac {b}{x^2}\right )^2} \, dx=\frac {3 x}{2 a^2}-\frac {x^3}{2 a \left (b+a x^2\right )}-\frac {3 \sqrt {b} \arctan \left (\frac {\sqrt {a} x}{\sqrt {b}}\right )}{2 a^{5/2}} \]
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Time = 0.01 (sec) , antiderivative size = 55, normalized size of antiderivative = 1.00, number of steps used = 4, number of rules used = 4, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.444, Rules used = {199, 294, 327, 211} \[ \int \frac {1}{\left (a+\frac {b}{x^2}\right )^2} \, dx=-\frac {3 \sqrt {b} \arctan \left (\frac {\sqrt {a} x}{\sqrt {b}}\right )}{2 a^{5/2}}+\frac {3 x}{2 a^2}-\frac {x^3}{2 a \left (a x^2+b\right )} \]
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Rule 199
Rule 211
Rule 294
Rule 327
Rubi steps \begin{align*} \text {integral}& = \int \frac {x^4}{\left (b+a x^2\right )^2} \, dx \\ & = -\frac {x^3}{2 a \left (b+a x^2\right )}+\frac {3 \int \frac {x^2}{b+a x^2} \, dx}{2 a} \\ & = \frac {3 x}{2 a^2}-\frac {x^3}{2 a \left (b+a x^2\right )}-\frac {(3 b) \int \frac {1}{b+a x^2} \, dx}{2 a^2} \\ & = \frac {3 x}{2 a^2}-\frac {x^3}{2 a \left (b+a x^2\right )}-\frac {3 \sqrt {b} \tan ^{-1}\left (\frac {\sqrt {a} x}{\sqrt {b}}\right )}{2 a^{5/2}} \\ \end{align*}
Time = 0.03 (sec) , antiderivative size = 51, normalized size of antiderivative = 0.93 \[ \int \frac {1}{\left (a+\frac {b}{x^2}\right )^2} \, dx=\frac {x}{a^2}+\frac {b x}{2 a^2 \left (b+a x^2\right )}-\frac {3 \sqrt {b} \arctan \left (\frac {\sqrt {a} x}{\sqrt {b}}\right )}{2 a^{5/2}} \]
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Time = 0.03 (sec) , antiderivative size = 42, normalized size of antiderivative = 0.76
method | result | size |
default | \(\frac {x}{a^{2}}-\frac {b \left (-\frac {x}{2 \left (a \,x^{2}+b \right )}+\frac {3 \arctan \left (\frac {a x}{\sqrt {a b}}\right )}{2 \sqrt {a b}}\right )}{a^{2}}\) | \(42\) |
risch | \(\frac {x}{a^{2}}+\frac {b x}{2 \left (a \,x^{2}+b \right ) a^{2}}+\frac {3 \sqrt {-a b}\, \ln \left (-\sqrt {-a b}\, x -b \right )}{4 a^{3}}-\frac {3 \sqrt {-a b}\, \ln \left (\sqrt {-a b}\, x -b \right )}{4 a^{3}}\) | \(72\) |
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Time = 0.25 (sec) , antiderivative size = 136, normalized size of antiderivative = 2.47 \[ \int \frac {1}{\left (a+\frac {b}{x^2}\right )^2} \, dx=\left [\frac {4 \, a x^{3} + 3 \, {\left (a x^{2} + b\right )} \sqrt {-\frac {b}{a}} \log \left (\frac {a x^{2} - 2 \, a x \sqrt {-\frac {b}{a}} - b}{a x^{2} + b}\right ) + 6 \, b x}{4 \, {\left (a^{3} x^{2} + a^{2} b\right )}}, \frac {2 \, a x^{3} - 3 \, {\left (a x^{2} + b\right )} \sqrt {\frac {b}{a}} \arctan \left (\frac {a x \sqrt {\frac {b}{a}}}{b}\right ) + 3 \, b x}{2 \, {\left (a^{3} x^{2} + a^{2} b\right )}}\right ] \]
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Time = 0.12 (sec) , antiderivative size = 83, normalized size of antiderivative = 1.51 \[ \int \frac {1}{\left (a+\frac {b}{x^2}\right )^2} \, dx=\frac {b x}{2 a^{3} x^{2} + 2 a^{2} b} + \frac {3 \sqrt {- \frac {b}{a^{5}}} \log {\left (- a^{2} \sqrt {- \frac {b}{a^{5}}} + x \right )}}{4} - \frac {3 \sqrt {- \frac {b}{a^{5}}} \log {\left (a^{2} \sqrt {- \frac {b}{a^{5}}} + x \right )}}{4} + \frac {x}{a^{2}} \]
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Time = 0.28 (sec) , antiderivative size = 45, normalized size of antiderivative = 0.82 \[ \int \frac {1}{\left (a+\frac {b}{x^2}\right )^2} \, dx=\frac {b x}{2 \, {\left (a^{3} x^{2} + a^{2} b\right )}} - \frac {3 \, b \arctan \left (\frac {a x}{\sqrt {a b}}\right )}{2 \, \sqrt {a b} a^{2}} + \frac {x}{a^{2}} \]
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Time = 0.27 (sec) , antiderivative size = 42, normalized size of antiderivative = 0.76 \[ \int \frac {1}{\left (a+\frac {b}{x^2}\right )^2} \, dx=-\frac {3 \, b \arctan \left (\frac {a x}{\sqrt {a b}}\right )}{2 \, \sqrt {a b} a^{2}} + \frac {x}{a^{2}} + \frac {b x}{2 \, {\left (a x^{2} + b\right )} a^{2}} \]
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Time = 5.91 (sec) , antiderivative size = 43, normalized size of antiderivative = 0.78 \[ \int \frac {1}{\left (a+\frac {b}{x^2}\right )^2} \, dx=\frac {x}{a^2}+\frac {b\,x}{2\,\left (a^3\,x^2+b\,a^2\right )}-\frac {3\,\sqrt {b}\,\mathrm {atan}\left (\frac {\sqrt {a}\,x}{\sqrt {b}}\right )}{2\,a^{5/2}} \]
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